- "
typename" is a
keyword in the C++
programming language used when
writing templates. It is used for
specifying that a
dependent name in a
template definition...
- m_stream(pstream) {}
template <
typename T> Printer& print(T&& t) {
m_stream << t;
return *this; }
template <
typename T> Printer& println(T&& t) { m_stream...
- Test {
typedef int foo; };
template <
typename T> void f(
typename T::foo) {} //
Definition #1
template <
typename T> void f(T) {} //
Definition #2 int main()...
- type =
typename concatenator<cnt - 1, std::tuple<
typename res< number<cnt> >::result, Args... >>::type;}; /** * Base case */
template <
typename... Args>...
- template<
typename F,
typename G,
typename X> auto apply(Composition<F, G> f, X arg) {
return apply(f.f, apply(f.g, arg)); } template<
typename T,
typename X>...
- this._typeName =
typeName; }
public function get
typeName():String {
return _
typeName; }
public static function getFruitByTypeName(
typeName:String):Fruit...
- template<
typename... Values>
class tuple; //
takes zero or more
arguments The
above template class tuple will take any
number of
typenames as its template...
- the
usual convention) */
template <
typename T>
struct rank {
static const std::size_t
value = 0; }; template<
typename T, std::size_t N>
struct rank<T[N]>...
-
KeyValuePair class with two
template parameters, as follows.
template <
typename Key,
typename Value>
class KeyValuePair {}; The
following is an
example of a class...
- saved.
template <
typename E1,
typename E2>
class VecSum :
public VecExpression<VecSum<E1, E2> > { // cref if leaf, copy
otherwise typename std::conditional<E1::is_leaf...
