Definition of Torsionless. Meaning of Torsionless. Synonyms of Torsionless

Here you will find one or more explanations in English for the word Torsionless. Also in the bottom left of the page several parts of wikipedia pages related to the word Torsionless and, of course, Torsionless synonyms and on the right images related to the word Torsionless.

Definition of Torsionless

No result for Torsionless. Showing similar results...

Meaning of Torsionless from wikipedia

- module M over a ring R is called torsionless if it can be embedded into some direct product RI. Equivalently, M is torsionless if each non-zero element of...
- any exact sequence of R-modules preserves exactness. Torsionless A module is called torsionless if it embeds into its algebraic dual. Simple A simple...
- Any torsionless module over a domain is a torsion-free module, but the converse is not true, as Q is a torsion-free Z-module that is not torsionless. Over...
- module is one for which the canonical homomorphism is an isomorphism. A torsionless module is one for which the canonical homomorphism is injective. Example:...
- }=A_{\beta }R^{\beta }{}_{\nu \rho \sigma }\,,} since the connection is torsionless, which means that the torsion tensor vanishes. This can be generalized...
- evaluation map, but it is not always injective; if it is, this is known as a torsionless module; if it is an isomophism, the module is called reflexive. For topological...
- (dualizing sheaf) on a normal projective variety is a divisorial sheaf. Torsionless module Torsion sheaf Twisted sheaf Hartshorne 1980, Corollary 1.2. Hartshorne...
- turn it into a Levi-Civita connection, i.e. to make a connection be torsionless. Indeed, if one writes θ for the solder form, then the torsion tensor...
- b}^{a}=0.} The difference between a connection with torsion, and the unique torsionless connection is given by the contorsion tensor. Connections with torsion...
- Einstein–Hilbert and Rarita–Schwinger actions now being written with a torsionless spin connection that explicitly depends on the vielbeins. The supersymmetry...