- 2023, UK Phages: We Are - Psy-Harmonics, 2023,
Australia Holeg Spies:
Notinism.org -
Remixes -
Liquid Sound Design, 2023, UK
Megan Rutherford & Holeg...
- {\displaystyle A\ [x\in B\iff x\
notin f(x)]} , we
deduce ξ ∈ B ⟺ ξ ∉ f ( ξ ) {\displaystyle \xi \in B\iff \xi \
notin f(\xi )} via
universal instantiation...
- 0 ∉ P 2 {\displaystyle \mathbf {0} \
notin P_{2}} and a + b ∉ P 2 ; {\displaystyle \mathbf {a} +\mathbf {b} \
notin P_{2};} it is an
affine subspace. Its...
- {\displaystyle P}
since b ∉ P {\displaystyle b\
notin P} , and conversely, if e ∉ P {\displaystyle e\
notin P} , we have φ e = φ a {\displaystyle \varphi...
- notation, A c = { a ∈ U : a ∉ A } {\displaystyle A^{\text{c}}=\{a\in U:a\
notin A\}} . The
complement may also be
called the
absolute complement to distinguish...
- {\displaystyle x\
notin x} for φ ( x ) {\displaystyle \varphi (x)} to get ∃ y ∀ x ( x ∈ y ⟺ x ∉ x ) {\displaystyle \exists y\forall x(x\in y\iff x\
notin x)} Then...
- {\displaystyle a_{i}\in \mathbb {O} } and e i ∉ O {\displaystyle e_{i}\
notin \mathbb {O} } An
algebra of
dimension 8 over
quaternions H {\displaystyle...
- {W_{U}}}\subseteq U\,} . For
every x ∉ U {\displaystyle x\
notin U} , we will
prove that x ∉ W U ¯ {\displaystyle x\
notin {\bar {W_{U}}}} .
Since we
chose V {\displaystyle...
- ∈ U : x ∉ A } . {\displaystyle A^{\complement }=U\setminus A=\{x\in U:x\
notin A\}.} The
absolute complement of A is
usually denoted by A ∁ {\displaystyle...
- ∧ ( b ∉ O ) {\displaystyle (a\in O)\wedge (b\
notin O)} or ( a ∉ O ) ∧ ( b ∈ O ) {\displaystyle (a\
notin O)\wedge (b\in O)} . Note that
topologically distinguishable...
