- 0 ∉ P 2 {\displaystyle \mathbf {0} \
notin P_{2}} and a + b ∉ P 2 ; {\displaystyle \mathbf {a} +\mathbf {b} \
notin P_{2};} it is an
affine subspace. Its...
- {\displaystyle A\ [x\in B\iff x\
notin f(x)]} , we
deduce ξ ∈ B ⟺ ξ ∉ f ( ξ ) {\displaystyle \xi \in B\iff \xi \
notin f(\xi )} via
universal instantiation...
- {\displaystyle P}
since b ∉ P {\displaystyle b\
notin P} , and conversely, if e ∉ P {\displaystyle e\
notin P} , we have φ e = φ a {\displaystyle \varphi...
- Y)\land (\forall Y_{1},Y_{2}\in p:Y_{1}\neq Y_{2}\rightarrow (x\
notin Y_{1}\lor x\
notin Y_{2})).} In the case that the left and
right coordinates are identical...
- ∈ U : x ∉ A } . {\displaystyle A^{\complement }=U\setminus A=\{x\in U:x\
notin A\}.} The
absolute complement of A is
usually denoted by A ∁ {\displaystyle...
- Jean-Christophe
Notin, La
guerre de la
France au Mali, p. 368. Jean-Christophe
Notin, La
guerre de la
France au Mali, pp. 347-350. Jean-Christophe
Notin, La guerre...
- {\displaystyle x\
notin x} for φ ( x ) {\displaystyle \varphi (x)} to get ∃ y ∀ x ( x ∈ y ⟺ x ∉ x ) {\displaystyle \exists y\forall x(x\in y\iff x\
notin x)} Then...
- \mid B)=\alpha P(\omega )} ω ∉ B : P ( ω ∣ B ) = 0 {\displaystyle \omega \
notin B:P(\omega \mid B)=0} ∑ ω ∈ Ω P ( ω ∣ B ) = 1. {\displaystyle \sum _{\omega...
- x ) = 0 {\displaystyle f_{X}(x)=0} for all x ∉ X ( S ) {\displaystyle x\
notin X(S)} as
shown in the figure. The
image of X {\displaystyle X} has a countable...
- edge in E {\displaystyle E} with u ∉ C {\displaystyle u\
notin C} and v ∉ C {\displaystyle v\
notin C} (an edge
unrelated to the cycle), then
include in E...
