Definition of Biholomorphisms. Meaning of Biholomorphisms. Synonyms of Biholomorphisms

Here you will find one or more explanations in English for the word Biholomorphisms. Also in the bottom left of the page several parts of wikipedia pages related to the word Biholomorphisms and, of course, Biholomorphisms synonyms and on the right images related to the word Biholomorphisms.

Definition of Biholomorphisms

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Meaning of Biholomorphisms from wikipedia

- only if f: U → f(U) is biholomorphic. Notice that per definition of biholomorphisms, nothing is ****umed about their derivatives, so, this equivalence contains...
- a biholomorphisms is locally in Γ, then it too is in Γ. The pseudogroup is said to be transitive if, given z and w in C, there is a biholomorphism f in...
- compact Hermitian symmetric spaces: K is the isometry group, and G is the biholomorphism group of M. Over the real numbers, a real flag manifold is also called...
- {\displaystyle L^{2}} inner product on this space is manifestly invariant under biholomorphisms of D, the Bergman kernel and the ****ociated Bergman metric are therefore...
- transformations of X and can be identified with a subgroup Γ of the group of biholomorphisms of X. The group Γ thus acts freely on X with compact quotient space...
- collection of all local Ck diffeomorphisms on Rn form a pseudogroup. All biholomorphisms between open sets in Cn form a pseudogroup. More examples include:...
- (U_{1}\cap U_{2})\to \psi (U_{1}\cap U_{2})} is a biholomorphism. Notice that since every biholomorphism is a diffeomorphism, and C n {\displaystyle \mathbb...
- holomorphic. At this time, ϕ {\displaystyle \phi } is called a U, V biholomorphism also, we say that U and V are biholomorphically equivalent or that they...
- student Steven R. Bell on Fefferman's theorem on the smooth extension of biholomorphisms to the boundaries of their domains. This work, published in Inventiones...
- \mathbb {C} } , and ****ume that f : U → V {\displaystyle f:U\to V} is a biholomorphism. Then f {\displaystyle f} and f − 1 {\displaystyle f^{-1}} have antiderivatives...