- \phi \colon U\to V} , we say that U and V are
biholomorphically equivalent or that they are
biholomorphic. If n = 1 , {\displaystyle n=1,}
every simply...
- n>1} , open
balls and open
polydiscs are not
biholomorphically equivalent, that is,
there is no
biholomorphic mapping between the two. This was
proven by...
-
between charts are
biholomorphic,
complex manifolds are, in particular,
smooth and
canonically oriented (not just orientable: a
biholomorphic map to (a subset...
-
around every point on the
sphere there is a
neighborhood that can be
biholomorphically identified with C {\displaystyle \mathbf {C} } . On the
other hand...
-
theorem says that a
simply connected domain in the
complex plane is "
biholomorphically equivalent" (i.e.
there is a
bijection between them that is holomorphic...
- Thus,
under this definition, a map is
conformal if and only if it is
biholomorphic. The two
definitions for
conformal maps are not equivalent.
Being one-to-one...
-
domain is a
proper subdomain of C n {\displaystyle \mathbb {C} ^{n}} ,
biholomorphically equivalent to C n {\displaystyle \mathbb {C} ^{n}} . That is, an open...
- is not all of C {\displaystyle \mathbb {C} } , then
there exists a
biholomorphic mapping f {\displaystyle f} (i.e. a
bijective holomorphic mapping whose...
-
holomorphic maps is holomorphic. The two
Riemann surfaces M and N are
called biholomorphic (or
conformally equivalent to
emphasize the
conformal point of view)...
- of G {\displaystyle G} as a
neighbourhood of 0 {\displaystyle 0} ).
Biholomorphic mapping –
Bijective holomorphic function with a
holomorphic inversePages...
