-
parallel to FB, then
square BAGF must be
twice in area to
triangle FBC. Therefore,
rectangle BDLK must have the same area as
square BAGF = AB2. By
applying steps...
-
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square BAGF must be
twice in area to
triangle FBC. Therefore,
rectangle BDLK must have the same area as
square BAGF = AB2. By
applying steps...
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